Find the area of the parallelogram with the following vertices:
(-2, 3), (5, 8), (3, 3), and (0,8)

-12.5

Step-by-step explanation:

To easily get the area of the parallelogram, we will label the vertices .

A= 1, -2 X1, y1

B= 5,8... X2, y2

C= 3,3 X3, y3

D= 0,8 X4, y4

Before that, let me state that:

The Area of a parallelogram is defined as :

1/2 det (X1 (y2 - y3) + X2 ( y3 - y1) + X3 (y1 - y2)

In the order from the question:

A = (-2(8-3) + 5(3-3) + 3( 3-8)) / 2

A = -2(5) + 5(0) + 3(-5)

A = -10 + 0 - 15 / 2

A = -25/2

A = -12.5

d

step-by-step explanation:

d

9.55 degrees.

step-by-step explanation:

the given angle is

1 cycle is equal to 2π radians. so 4π will be equal to two cycles.

5.166667π-4π = 1.166667π

hence, this angle goes a little more than negative x axis.

1.166667π-π= 0.166667π

hence, the reference angle is 0.166667π radians.

1 radian = 57.2958 degrees

now, in degrees, this should be equals to 9.55 degrees.