The first term of a geometric sequence is 512
and the common ratio is 1/2 what is the
8th term?

Step-by-step explanation:

hello :

the n-ieme term is : An=A1×r^(n-1)

A1 the first term       r : the common ratio

in this exercice : A1 =512       r = 1/2            n = 8

A8=512×(1/2)^(8-1) = 512×(1/2)^7    

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step-by-step explanation:

median is the value separating the higher half of a data sample, a population or probablity distribution from the lower half.

step-by-step explanation:

say you have 3,8,7,3,1,9,8 order them from lowest to highest

if orderd it would be 1,3,3,7,8,8,9 now you take away from the lowest and the highest until you end up in the middle.

so you would remove the 1 and 9 leaving you with 5 digits remaining

when you've reached the middle that would be your answer so in this case the answer is 7

if there were two numbers left say 7 and 5 you'd and them together so 12 then divide by 2 witch would equal 6 so the answer would be 6

good luck on that project hoped i you at all