Prof. Shanks assigns 5 students to work on a project. The group is to have no more than 1 freshman. In how many ways can the group be selected if there are 5 freshmen and 10 sophomores in the class?

1302

Step-by-step explanation:

10C5 + (5C1×10C4) = 1302

b is the final answer! : )

(n^3 - n)

= n(n-1)(n+1)

since it is divisible by 3 and 2 ,because it is a multiple 3 consecutive number

if, n-1 is odd then n+1 is also odd, then it is a multiple of 9

but if, n-1 is even then n+1 is also even, then it is a multiple of 4

so, largest multiple = max(9*2, 4*3) = max(18, 12) = 18