Assume the sample variances to be continuous measurements. Find the probability that a random sample of 24 observations, from a normal population with variance σ2 = 6, will have a sample variance S2 less than 2.946.

Step-by-step explanation:

Hello!

You have a random sample of 24 observations from a normal population with variance δ²= 6.

The distribution of the sample variance is

X²= ~

Using this distribution you can calculate the asked probability:

P(S²<2.946)= P(X²<)= P(X²<11.293)

Now you have to look for the probability in the table of the Chi-square distribution, this particular distribution has n-1= 24-1=23 degrees of freedom, so you have to look for the probability under X²₂₃

P(X²<11.293) = 0.02

I hope this helps!

its 4 because 2 times 2 is 4, if you double the number two you get four