The computer that controls a bank's automatic teller machine crashes a mean of 0.60.6 times per day. What is the probability that, in any seven-day week, the computer will crash more than 33 times? Round your answer to four decimal places.

0.6045 = 60.45% probability that, in any seven-day week, the computer will crash more than 3 times.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

In which

x is the number of sucesses

e = 2.71828 is the Euler number

is the mean in the given time interval.

The computer that controls a bank's automatic teller machine crashes a mean of 0.6 per day.

7 day week, so

What is the probability that, in any seven-day week, the computer will crash more than 3 times?

Either it crashes 3 or less times, or it crashes more than 3 times. The sum of the probabilities of these events is decimal 1. So

We want P(X > 3). So

In which

0.6045 = 60.45% probability that, in any seven-day week, the computer will crash more than 3 times.

3-4

step-by-step explanation:

the answer is 3-4 because both 45 and 60 has a multiple of 15.

45/3=15

60/4=15

therefore the odds against selecting a red is 4-3

it is true

step-by-step explanation:

all the combinations add up i used   calculator