The number of square feet per house are normally distributed with a population standard deviation of 197 square feet and an unknown population mean. If a random sample of 25 houses is taken and results in a sample mean of 1820 square feet, find a 99% confidence interval for the population mean.

The 99% confidence interval for the population mean is betwen 1718.55 square feet and 1921.45 square feet.

Step-by-step explanation:

We have that to find our level, that is the subtraction of 1 by the confidence interval divided by 2. So:

Now, we have to find z in the Ztable as such z has a pvalue of .

So it is z with a pvalue of , so

Now, find M as such

In which is the standard deviation of the population and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 1820 - 101.45 = 1718.55 square feet

The upper end of the interval is the sample mean added to M. So it is 1820 + 101.45 = 1921.45 square feet.

The 99% confidence interval for the population mean is betwen 1718.55 square feet and 1921.45 square feet.

based on context clues you gave i'm assuming the answer would be c.

5050

hope this !