x^2 + 6x + y^2 + 4y + 12 = 0
Mathematics, 20.03.2020 18:31, Aliciaonfleek
Find the center and the radius of the circle with the equation:
x^2 + 6x + y^2 + 4y + 12 = 0
a.
center: (3, 2)
radius: 1
c.
center: (6, 4)
radius: 12
b.
center: (-3, -2)
radius: 1
d.
center: (-6, -4)
radius: 12
Answers: 1
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Lassify the function as linear or quadratic and identify the quadratic, linear, and constant terms. f(x) = (3x + 2)(−6x − 3) linear function; linear term: −21x; constant term: −6 linear function; linear term: −18x2; constant term: −6 quadratic function; quadratic term: 6x2; linear term: 24x; constant term: −6 quadratic function; quadratic term: −18x2; linear term: −21x; constant term: −6
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Find the center and the radius of the circle with the equation:
x^2 + 6x + y^2 + 4y + 12 = 0
x^2 + 6x + y^2 + 4y + 12 = 0
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