Find the line integral of f(x, y)= ye^x^2 along the curve r(t)= 4ti-3tj, -1<= t <= 1The integral of f is ??

Integrating function f implies that the parts of the function are added up to find the whole

The integral of f is 0.

The given parameters are:

means that:

Start by calculating: r->

So, the integrand is:

This gives

Substitute values for x and y

Remove the constant

Represent

with u.

So, we have:

When t = 1 and -1, we have:

Differentiate

Make t dt the subject

So, we have:

Integrate

Expand

Hence, the integral of f is 0.

Read more about integration at:

link

Let , so that :

x = -4

step-by-step explanation:

- 20 - 4(x + 3) = 4x

=> -20 - 4x - 12 = 4x

=> - 32 -4x = 4x

=> -32 = 4x + 4x

=> - 32 = 8x

=> -32/8 = x

=> -4 = x

y=3x+4

step-by-step explanation:

given the points a(0,4) and b(-4, -8)

eqn of line ab: (y-4)/(x-0)=(-8-4)/(-4-0)

(y-4)/x=-12/-4=3

y=3x+4