A polynomial has been factored below, but some constants are missing. 2x^3 –6x^2 –8x=ax(x+b)(x+c) What are the missing values of a, b, and c?

Step-by-step explanation:

hello :

2x^3 –6x² –8x=ax(x+b)(x+c)

2x^3 –6x² –8x= 2x(x²-3x-4)

but : x²-3x-4 = (x+1)(x-4)

so : 2x^3 –6x² –8x= 2x(x+1)(x-4)

a=2    and     b=1   and     c= -4

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3

no association

step-by-step explanation:

if you have eyes and you can use them efficiently you can see that it just looks like random dots like do a line of best fit and like they're so spread out it's such a weak association you might as well consider it nonexistent