Find the equation of a line perpendicular to y=−2x+3 that contains the point (1,−4). Write the equation in slope-intercept form.

y = 1/2 x -9/2

Step-by-step explanation:

y = -2x+3

The slope is -2

We want a line perpendicular.  The product of the slopes is -1

-2 *m = -1

Divide by -2

-2m/-2 = -1/-2

m = 1/2

The slope of the perpendicular line is 1/2

The slope intercept form of a line is

y = mx+b

y = 1/2x+b

We have the point (1,-4).  Substituting in for x and y

-4 = 1/2(1) +b

-4 = 1/2+b

Subtract 1/2 from each side

-4 -1/2 = b

-8/2 -1/2 =b

-9/2 =b

The equation for the line in slope intercept form is

y = 1/2 x -9/2

true? is that what you're asking or do you mean something else?