Mathematics
Mathematics, 20.03.2020 11:29, smolemily

Define the exponentiation operator on naturals recursively so that x0 = 1 and xS(y) = xy · x. Prove by induction, using this definition, that for any naturals x, y, and z, xy+z = xy · xz and xy·z = (xy)z.

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Define the exponentiation operator on naturals recursively so that x0 = 1 and xS(y) = xy · x. Prove...

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