On the first day of spring, an entire field of flowering trees blossoms. The population of locusts consuming these flowers rapidly increases as the trees blossom. The locust population gains 87\%87%87, percent of its size every 2.42.42, point, 4 days, and can be modeled by a function, LLL, which depends on the amount of time, ttt (in days).
Before the first day of spring, there were 1100 locusts in the population.

Every day, the locust population grows by a factor of 1.30.

Step-by-step explanation:

"Complete the following sentence about the daily rate of change of the locust population."

The population of locusts changes exponentially.  Initially, there are 1100 locusts.  Every 2.4 days, the population increases by 87%.  So the equation L(t) is:

L(t) = 1100 (1.87)^(t/2.4)

After 1 day, the population is:

L(1) = 1100 (1.87)^(1/2.4)

L(1) = 1428

Compared to the initial 1100, the population increases by a factor of:

1428 / 1100 = 1.30

Since the daily rate of change is greater than 1, the population grows.

  b.   the average rate of change of f(x) is less than the average rate of change of g(x).

step-by-step explanation:

since the length of the interval is the same in each case, we only need to compare the change in y-value to see which is greater.

so the change in y-value for function f is (6 )) = 9.

the table tells us

so the change in y-value for function g is (31 -1) = 30.

the change in y-value of f(x) on the interval is less than the change in y-value of g(x) on the same interval, so the average rate of change of f(x) is less than the average rate of change of g(x).

1) is right

step-by-step explanation: