The extract of a plant native to Taiwan has been tested as a possible treatment for Leukemia. One of the chemical compounds produced from the plant was analyzed for a particular collagen. The collagen amount was found to be normally distributed with a mean of 78 and standard deviation of 9.9 grams per mililiter.(a) What is the probability that the amount of collagen is greater than 62 grams per milliliter?
(b) What is the probability that the amount of collagen is less than 74 grams per milliliter?
(c) What percentage of compounds formed from the extract of this plant fall within 1 standard deviation of the mean?

Step-by-step explanation:

Given that extract of a plant native to Taiwan has been tested as a possible treatment for Leukemia.  Let X be the collagen amount produced form the plant

X is N(78, 9.9) gm/mm

a)  the probability that the amount of collagen is greater than 62 grams per milliliter?

=

(b)  the probability that the amount of collagen is less than 74 grams per milliliter?

=

c) As per normal distribution rule, 68% lie within 1 std dev form the mean.

(c) percentage of compounds formed from the extract of this plant fall within 1 standard deviation of the mean?

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)

1/3

step-by-step explanation:

to find this, you can divide 12 by 4 which is 3 or you can multiply 4 until you reach 12 (4x3=12). both should give you 3, meaning theres three times less bananas than there are oranges.