(i) 1 1 is in S. (ii) If a b is in S, where a b is written in lowest terms (that is, a and b have highest common factor 1), then b 2a is in S. (iii) If a b and c d are in S, where they are written in lowest terms, then a+c b+d is in S.

answer: 48

just remember to use pemdas:

parentheses

expressions

multiplication

division

addition

subtraction

answer: 4 meters

step-by-step explanation: to you understand 2/3 better you can do 1 divided by 3 = . then multiply that by the 2 which is .66666666666666667 then you would do 6 x .66666666666666667 which is 4.      

hope this .

guess at question:

a vertical line intersects the graph of g(x,y) = 0 at two points. what conclusion follows about the function f(x) implicitly defined by g(x,f(x)) = 0?

the domain of f(x) cannot include the x coordinate of any such vertical line.

informally, f(x) is not a function, and

g(x,y)=0 cannot be solved for y uniquely.

the relation r = {(x,y) such that g(x,y) = 0} is a function if

for all (a,b) ∊ r and (c,d) ∊ r, a=c implies b=d.

step-by-step explanation:

(0.2)+(-8)=0.3+-3+0.3m is the equation i guess? ?

step-by-step explanation: