A spherical balloon is inflating with helium at a rate of 64 pi StartFraction ft cubed Over min EndFraction . How fast is the balloon's radius increasing at the instant the radius is 2 ft?

The radius of the balloon is increasing at a rate of 4 feet per minute.

Step-by-step explanation:

We are given the following in the question:

Volume of sphere is given by

where r is the radius of the balloon.

Instant radius, r = 2 ft

Rate of change of volume =

Putting values, we get,

Thus, the radius of the balloon is increasing at a rate of 4 feet per minute.

the correct answer option is (2x-3)(2x+3).

step-by-step explanation:

we are given the following expression and we are to factorize it:

we are to find such factors that when multiplied they give a result of 36 (9 x 4 = 36) and when added they give a result of 0.

the two such factors of 36 are negative six and postive six.

factorizing the given expression to get:

therefore, the correct factorization of is (2x-3)(2x+3).