Smalltown has two water filters that clean the town's drinking water. Filter A can filter up to 159.93 gallons of water per minute, and filter B can filter up to 169.86 gallons of water per minute. About how much water can be filtered by these two filters for Smalltown in 75 minutes?

The total quantity that can be filtered by both the filters in 75 minutes is 24734.25 gallons

Step-by-step explanation:

Step 1:

Given

Quantity of water that can be filled by filter A in one minute =  159.93 gallons

Quantity of water that can be filled by filter B in one minute = 169.86 gallons

We need to compute the total of the water that the 2 filters can filter in 75 minutes

Step 2 :

The total quantity that can be filtered by both the filters in one minute =   159.93 + 169.86  = 329.79 gallons

The total quantity that can be filtered by both the filters in 75 minutes =    329.79 × 75 = 24734.25 gallons

Step 3 :

Answer :

The total quantity that can be filtered by both the filters in 75 minutes is 24734.25 gallons

Filter A can filter 11994.75 gallons of water  & Filter B can filter 12739.50 gallons of water , both in 75 minutes . Also Both give (  11994.75  + 12739.50 ) = 24734.25 gallons of water .

Step-by-step explanation:

Here we have , Small town has two water filters that clean the town's drinking water. Filter A can filter up to 159.93 gallons of water per minute, and filter B can filter up to 169.86 gallons of water per minute. . We need to find that About how much water can be filtered by these two filters for Small town in 75 minutes . Let's solve this :

Filter A:

Filter A can filter up to 159.93 gallons of water per minute , in 1 min it fills 159.93 gallons of water so , in 75 min

⇒

⇒ , i.e. in 75 min it fills 11994.75 gallons of water .

Filter B:

Filter B can filter up to 169.86 gallons of water per minute , in 1 min it fills 169.86 gallons of water so , in 75 min

⇒

⇒ , i.e. in 75 min it fills 12739.50 gallons of water .

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2