To accumulate 8000 at the end of 3n years, deposits of 98 are made at the end of each of the first n years and 196 at the end of each of the next 2n years. The annual effective rate of interest is i. You are given (1 ) 2.0 n + = i .

Step-by-step explanation:

The accumulative value for n years will be:

=

The accumulative value for 2n years will be:

=4* 98/i

=              .....called it equation 1

The accumulative value for 3n years will be:

=

=                   ....called it equation 2

Now sum equation 1 and equation 2 together

+=8000

divide both side by 980 to get i

i =

step-by-step explanation:

once you graph it hit 2nd (the blue button) and graph

that takes you to a table of coordinates

on the left is x coordinates and on the right is y coordinates and an empty box

(you may have to scroll up/down in order to get ( x, 0)