Use cylindrical coordinates to evaluate the triple integral dV= function equation editor , where EE is the region that lies inside the cylinder x2+y2=4x2+y2=4 and between the planes z=2z=2 and z=7z=7.

The cilinder x^{2} + y^{2} = 4 has the form x^{2} + y^{2} = r^{2}. Here, the radius of the cilinder is 2.

It is only necessary to solve the next integral by taking into account the correct limits :

I hope this is usefull for you

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option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

im pretty sure it would be 5 am, hope that , and give brainliest and guys if this is right then press the button and give 5 stars