Two cans of soup and three bags of chips cost $10.30. Four cans of soup and two bags of chips cost $14.20. What is the cost for each item sold separately?

A can of soup costs $2.75, while a bag of chips costs $1.6

Step-by-step explanation: We shall start by first assigning letters to the unknown variables. Let each can of soup be represented by c, and let each bag of chips be represented by b.

If two cans of soup and three bags of chips cost $10.30, then we can write this out as,

2c + 3b = 10.30

Also, if four cans of soup and two bags of chips cost $14.20, we can write this too as,

4c + 2b = 14.20

What we now have is a pair of simultaneous equations

2c + 3b = 10.30 (1)

4c + 2b = 14.20 (2)

None of the variables has a coefficient of 1, hence we shall use the elimination method

Multiply equation (1) by 4 and multiply equation (2) by 2.

We now have,

8c + 12b = 41.20 (3)

8c + 4b = 28.40 (4)

Subtract equation (4) from equation (3)

8b = 12.80

Divide both sides of the equation by 8

b = 1.60

Having computed the value of b, we can now substitute for the value of b into equation (1)

2c + 3(1.60) = 10.30

2c + 4.80 = 10.30

Subtract 4.80 from both sides of the equation

2c = 5.50

Divide both sides of the equation by 2

c = 2.75

Therefore a bag of chips is $1.60, a can of soup is $2.75

the answer is a

step-by-step explanation:

39.00 x 24 = total installment price

carrying installment price - cash price

needed to save the .00/

correct choice is b

step-by-step explanation:

when you calculate the average rate of change of a function, you are finding the slope of the secant line between the two points. for the function the average rate of change from point to point can be calculated as

to find the average rate of change from day 2 to day 10, note that at day 2, 8 houses were sold, so a(2,8) and at day 10, 2 houses were sold, so b(10,2). thus,