How does the mean absolute deviation (mad) of the data in set 2 compare to the mean absolute deviation of the data in set 1? set 1: 16, 15, 10, 12 set 2: 16, 62, 15, 10, 12 the mad of set 2 is 10 less than the mad of set 1. the mad of set 2 is 13.35 more than the mad of set 1. the mad of set 2 is 10 more than the mad of set 1. the mad of set 2 is 13.35 less than the mad of set 1.

The MAD of the set 2 is 13.35 more than the MAD of set 1.

Step-by-step explanation:

The mean absolute deviation of the set 1 (16, 15, 10, 12) is:

Mean of the set1:

Distances of each data from the mean :

|16 -13.25| = 2.75

|15-13.25| = 1.75

|10-13.25| = 3.25

|12-13.25| = 1.25

Mean of those distances=

Thus, mean absolute deviation of the set 1 is 2.25.

The mean absolute deviation of the set 2(16, 62, 15, 10, 12) is :

Mean of the set 2:

Distances of each data from the mean :

|16 -23| = 7

|62-23| = 39

|15-23| =8

|10-23| = 13

|12-23| = 11

Mean of those distances =

Thus, mean absolute deviation of the set 1 is 15.6.

Mean absolute deviation of data set 2 - Mean absolute deviation of data set 1 = 15.6-2.25=13.35.

Thus, The MAD of the set 2 is 13.35 more than the MAD of set 1.

the answer is 510

step-by-step explanation:

15 • 13 = 195

15 • 12 = 180

15 • 5 = 75

12 • 5 = 60

195 + 180 = 375

375 + 75 = 450

450 + 60 = 510