The volume V of a right circular cylinder of radius r and height h is V=πr2h. (a) How is dVdt related to drdt if h is constant and r varies with time? (Enter drdt as dr/dt.)

Step-by-step explanation:

Given that the  volume V of a right circular cylinder of radius r and height h is

To find rate of change of V with respect to rate of change of radius

Here given that h is constant

So differentiation with respect to t gives

This would be dv/dt i.e. rate of change of volume with respect to time in terms of dr/dt

This varies whenever r varies

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116