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Mathematics, 19.03.2020 01:08, auraziabagley
M∠ABD=96 ∘ m, angle, A, B, D, equals, 96, degrees \qquad m \angle CBD = 6x + 27^\circm∠CBD=6x+27 ∘ m, angle, C, B, D, equals, 6, x, plus, 27, degrees \qquad m \angle ABC = 7x - 9^\circm∠ABC=7x−9 ∘ m, angle, A, B, C, equals, 7, x, minus, 9, degrees Find m\angle CBDm∠CBDm, angle, C, B, D:
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M∠ABD=96 ∘ m, angle, A, B, D, equals, 96, degrees \qquad m \angle CBD = 6x + 27^\circm∠CBD=6x+27 ∘ m...
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