What are the values of a, b, and c in the quadratic equation 0 = x2 – 3x – 2? - a = , b = 3, c = 2 - a = , b = –3, c = –2 - a = , b = 3, c = –2 - a = , b = –3, c = 2

a = 1, b = –3, c = –2

Step-by-step explanation:

The A, B, and C of the equation are the numeric values that the quadratic "x" the X and the numeric value of the equation has, like this:

A

So when you get the equation you can see that the values are:

So A would be: 1

B would be: -3

And C would be:-2

find the magnitude of the trig term  

csc

(

x

)

−

1

by taking the absolute value of the coefficient.

1

find the lower bound of the range.

tap for more

y

=

−

2

find the upper bound of the range.

tap for more

y

=

0

the range is  

y

≤

−

2

or  

y

≥

0

.

(

−

∞

,

−

2

]

∪

[

0

,

∞

)

{

y

|

y

≤

−

2

,

y

≥

0

}

step-by-step explanation: