Wavelength varies inversely with frequency. Let k be the product of wavelength and frequency. Complete
the table using the inverse variation relationship.
Visible Light
Wavelength (m)
Frequency (THz)
Blue
450
301,500
Green
520
580
Yellow
540
302,400
Red
635
304,800
480
a=
b = 301,
c=_
DONE

A=670

B=301,600

C=560

Step-by-step explanation:

A is K divided by the wavelength (m) 301,500 / 450

B is wavelength(m) multiplied by the Frequency (Thz) 520x580

C is K divided by the Frenquency (Thz) 302400 / 540

xy = 302,400

Step-by-step explanation:

Part 2 of the question

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.

answer is because 4×10=40

and 98×4= is 392

40,392