You have a jar of jelly beans in front of you

with 12 - lime, 17 - papaya, 5 - mango and 13

- bubble gum. What is the probability, as a

fraction, of selecting either a lime or bubble

gum followed by a papaya?

The probability of selecting either a lime or bubble gum followed by a papaya is 425/2209

Step-by-step explanation:

Since, there are four types of items in the jar, namely- lime, papaya, mango and bubble gum that have quantities of 12, 17, 5 and 13 respectively. Before finding the probabilities, we first add up the quantities or number of different items in the jar.

12 + 17 + 5 + 13 = 47 in total.

Since lime is 12 in number, the probability of selecting a lime is = 12/47.

Bubble gums are 13 in number, so the probability of selecting a bubble gum = 13/47.

Then the probability of selecting either a lime or a bubble gum is the addition of the probabilities of selecting a lime and selecting a bubble gum:

= 12/47 + 13/47

= 25/47.

Again, the probability of selecting a papaya is =

number of papaya/total number of items

= 17/47

If the system is with replacement, then the probability of selecting a lime or bubble gum followed by a papaya is:

= Probability of selecting a lime or bubble gum × Probability of selecting papaya

= 25/47 × 17/47

= 425/2209

The probability of selecting a lime or bubble gum followed by a papaya is 425/2209

rounding to the nearest thousandth would be 452,000

the cat is blue because the probability of extension towards the prefix of the diameter of the circle could only mathematically equal to the sum of the roots of the carrots from   your garden.

step-by-step explanation: