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Mathematics, 15.10.2019 03:30, GusGus11
The work of a student to solve a set of equations is shown: equation a: y = 15 β 2z equation b: 2y = 3 β 4z step 1: β2(y) = β2(15 β 2z) [equation a is multiplied by β2.] 2y = 3 β 4z [equation b] step 2: β2y = 15 β 2z [equation a in step 1 is simplified.] 2y = 3 β 4z [equation b] step 3: 0 = 18 β 6z [equations in step 2 are added.] step 4: 6z = 18 step 5: z = 3 in which step did the student first make an error? step1 step 2 step 3 step 4
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The work of a student to solve a set of equations is shown: equation a: y = 15 β 2z equation b: 2...
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