Equations with the Dependent Variable Missing For a second-order differential equation of the form y′′=f(t, y′), the substitution v=y′, v′=y′′ leads to a first-order equation of the form v′=f(t, v). If this equation can be solved for v, then y can be obtained by integrating dydt=v. Note that one arbitrary constant is obtained in solving the first-order equation for v, and a second is introduced in the integration for y. Use this substitution to solve the given equation. Note: All solutions should be found. 32t2y′′+(y′)3=32ty′, t>0 Use C1=C and C2=D as the constants of integration.