The engine sprocket of gino’s go-cart is 3cm in diameter. It is attached to an 18-cm rear axle sprocket that drives the go-cart. Find the angular velocity of the rear axle when the engine is turning 4,800 rpm.

Step-by-step explanation:

Given:

w = 4400 rev per minute

= 4400 × 2pi rad/1 rev × 1 min/60 sec

= 460.8 rad/s

R = 3cm

Ra = 18 cm

Since the sprocket is attached directly to the rear axle, it rotates exactly as the rear axle does: every revolution of the rear axle is a revolution of the sprocket. Hence, the angular speed of the rear axle sprocket = angular speed of the sprocket

= 460.8 rad/s

2/5

step-by-step explanation:

hope it

step-by-step explanation:

x^(1/6) · x^(1/6) · x^(1/6)   ·x^(1/6) = x^(4/6)   since we add the exponents

4/6 can be simplified to 2/3

the simplified form is x^(2/3)