Y= x2 − 6x 8 2y x = 4 the pair of points representing the solution set of this system of equations and

Some operators are missing.
If the right equations are y = x^2 -6x +8 and 2y + x =4
This is the solution

2y + x = 4
2y = -x +4
y = -x/2 + 2

y = x^2 -6x + 8 = -x/2 + 2

2x^2 - 12x + 16 = -x + 4
2x^2 -11x +12 = 0

Factor

(x-4)(2x-3)=0

x= 4 and x =3/2

y = -x/2 +2
 
y = -4/2 + 2 = 0
y = - (3/2)/2 + 2 = -3/4 + 2 = 5/4

Answer (4,0) and (3/2, 5/4)