What is the value of p such that the line passing through (9,-1) and (6,p) has a slope of -1?

Step-by-step explanation:

Slope, m =change in value of y on the vertical axis / change in value of x on the horizontal axis represent

change in the value of y = y2 - y1

Change in value of x = x2 -x1

y2 = final value of y

y 1 = initial value of y

x2 = final value of x

x1 = initial value of x

The line passes through (9,-1) and (6,p) and the slope is 1

y2 = p

y1 = - 1

x2 = 6

x1 = 9

Therefore,

(p - - 1)/(6 - 9) = - 1

(p + 1)/- 3 = - 1

(p + 1) = - 1 × - 3

p + 1 = 3

p = 3 - 1

p = 2

answer: y = -12x + 108

step-by-step explanation: do (y = m x+b) formula.