Dave has a collection of 47 coins. Some are $10 coins and the rest are $20 coins. If the face value is $710, how many of each denomination does he have?

he had twenty three $10 coins and twenty four $20 coins.

Step-by-step explanation:

Let x represent the number of $10 coins that he has.

Let y represent the number of $20 coins that he has.

Dave has a collection of 47 coins. This means that

x + y = 47

Some are $10 coins and the rest are $20 coins. If the face value is $710, it means that

10x + 20y = 710- - - - - - - - - -1

Substituting x = 47 - y into equation 1, it becomes

10(47 - y) + 20y = 710

470 - 10y + 20y = 710

- 10y + 20y = 710 - 470

10y = 240

y = 240/10

y = 24

x = 47 - y = 47 - 24

x = 23

46.2+112.3

step-by-step explanation:

the answer is:

the answer is:

to solve the problem, we need to remember the quotient of power property, it's defined by the following relation:

if we have a quotienf of powers that have the same base, we need to keep the same base and subtract the exponent of the denominator power to the exponent of the numerator power.

so, we are given the expression:

then, calculating we have:

hence, the answer is:

have a nice day!