Carl used 10 2/9 an inch of string to tie a parcel and another 5 1/4 of an inch of string to tie a box, how much string is left he started with 20 inches

20-(10 2/9)-(5 1/4)= 4.52777777778 inches decimal or 163/36

Step-by-step explanation:

Simplify the following:

20 - (10 + 2/9) - (5 + 1/4)

Put 10 + 2/9 over the common denominator 9. 10 + 2/9 = (9×10)/9 + 2/9:

20 - (9×10)/9 + 2/9 - (5 + 1/4)

9×10 = 90:

20 - (90/9 + 2/9) - (5 + 1/4)

90/9 + 2/9 = (90 + 2)/9:

20 - (90 + 2)/9 - (5 + 1/4)

90 + 2 = 92:

20 - 92/9 - (5 + 1/4)

Put 5 + 1/4 over the common denominator 4. 5 + 1/4 = (4×5)/4 + 1/4:

20 - 92/9 - (4×5)/4 + 1/4

4×5 = 20:

20 - 92/9 - (20/4 + 1/4)

20/4 + 1/4 = (20 + 1)/4:

20 - 92/9 - (20 + 1)/4

20 + 1 = 21:

20 - 92/9 - 21/4

Put 20 - 92/9 - 21/4 over the common denominator 36. 20 - 92/9 - 21/4 = (36×20)/36 + (4 (-92))/36 + (9 (-21))/36:

(36×20)/36 + (4 (-92))/36 + (9 (-21))/36

| 3 | 6

× | 2 | 0

| 0 | 0

7 | 2 | 0

7 | 2 | 0:

720/36 + (4 (-92))/36 + (9 (-21))/36

4 (-92) = -368:

720/36 + (-368)/36 + (9 (-21))/36

9 (-21) = -189:

720/36 - 368/36 + (-189)/36

720/36 - 368/36 - 189/36 = (720 - 368 - 189)/36:

(720 - 368 - 189)/36

720 - 368 - 189 = 720 - (368 + 189):

(720 - (368 + 189))/36

| 1 | 1 |  

| 3 | 6 | 8

+ | 1 | 8 | 9

| 5 | 5 | 7:

(720 - 557)/36

| | 11 |  

| 6 | 1 | 10

| 7 | 2 | 0

- | 5 | 5 | 7

| 1 | 6 | 3:

163/36

529 and 531

step-by-step explanation:

it would open into a square depending on the type of envelope i’m not sure about the second part