The base of the 37 foot ladder is 9 feet from the wall of a building. will the top of the ladder reach a window ledge 35 feet above the ground?

-I know its a yes but what is the math in it?

The answer to your question is Yes.

Step-by-step explanation:

The math in this problem is that we need to use the Pythagorean theorem to solve it. Pythagorean theorem is part of trigonometry a branch of Maths.

Data

base = 9 ft                      

length = 37 ft

height = ?

Pythagorean theorem

                                     c² = a² + b²

length = c

base = a

height = b

                                   37² = 9² + b²

-Solve for b

                                    b² = 37² - 9²

-Simplify

                                    b² = 1369 - 81

                                    b² = 1288

-Result

                                   b = 35.88

-Conclusion

The ladder will reach a height higher than 35 ft.  

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2

english, cause i can’t you