Tom's house is located at point (-2, 3) and the school is located at point (-2, -5). What is the distance between Tom's house and the school? Group of answer choices

8 units.

Step-by-step explanation:

We have been given that Tom's house is located at point (-2, 3) and the school is located at point (-2, -5). We are asked to find the distance between Tom's house and the school.

We will use distance formula to solve our given problem.

Let point and point .

Upon substituting the coordinates of given points in distance formula, we will get:

Therefore, the distance between Tom's house and the school is 8 units.

answer: expected value of x = 1.0

step-by-step explanation:

p(x=0) = 0.25

p(x=1) = 0.50

p(x=2) = 0.25

expected value for x = 0×0.25 + 1×0.5 + 2×0.25 = 1.0

answer: -8.2562234e+13