Prove algebraically what type of function this is (even, odd, or neither).

The given function is even.

Solution:

Given function:

If f(-x) = -f(x), then the function is odd.

If f(-x) = f(x), then the function is even.

Substitute x = -x

          = f(x)   (given)

   f(-x) = f(x)

From the definition, it is even.

Hence the given function is even.

i think it's ф or x=6,-6

step-by-step explanation:

-x^2=-36

x^2=-36

ф

or

if you mean by : -(x^2)=-36

it'll be: x^2=36

x=6,x=-6

hope it'll ! have a good day!

you for asking!

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.