Hudson and Katie are in a race and Hudson is running at 8-8 feet per sec. Katie gets 30 feet head start and is running in 6.3 feet per sec. How many sconds will it take until hudson and kaite to meet

12s.

Step-by-step explanation:

Given:

Hudson's velocity, Vh = 8.8 ft/s

Katie's velocity, Vk = 6.3 ft/s

Kate's head start distance, Dk = 30 ft

From the above, Katie and Hudson meet at th = tk = t

But, Dk = Dh + 30

Velocity = Distance/time

t × Vk = Dk

t × Vh = Dh

t × Vk + 30 = Dk

t × Vk + 30 = Vh × t

6.3t + 30 = 8.8t

t = 30/2.5

= 12 s