Use the Laws of Logarithms to combine the expression.
2(log6(x) + 3 log6(y) − 5 log6(z))

Log6(x² y⁶ / z¹⁰)

Step-by-step explanation:

Taking into account that

Log6(x)+log6(y)=log6(xy),

Log6(x)-log6(y)=log6(x/y)

And a×log6(x)=log6(x^a)

We have:

2(log6(x) + 3 log6(y) − 5 log6(z))=

2(log6(x) + log6(y³) − log6(z⁵))

2 log6(x y³ / z⁵)

Log6(x² y⁶ / z¹⁰)

i think is g(1)=-1.

hope that i can

3 is greater then both of those numbers