Henry’s age is 10 years less than 4 times Paul’s age. If the sum of their ages is equal to 25 years, find the age of each boy.

18 yrs and

7 years

Step-by-step explanation:

Let Henry’s age be A and Paul’s age be B

Given Henry’s age A is 10 yrs less than 4 times Paul’s age B.

That’s

A =4 x B - 10

A = 4B - 10

The sum of their ages is equal to 25

That’s

A + B = 25

Therefore,we no now have to equations

1. A = 4B - 10

2. A + B = 25

Now put 4B - 10 in place of A in equation 2

We have

A + B = 25

4B - 10 + B = 25

This can also be written as

4B + B - 10 = 25

5B - 10 = 25

Add 10 to both sides

5B - 10 + 10 = 25 + 10

5B = 35

Divide both sides by 5

5B/5 = 35/5

B = 7

Paul’s age = 7 yrs

Recall A = 4B - 10

and B= 7

Therefore,

A = 4 x 7 - 10

A = 28 - 10

A = 18

Henry’s age = 18 yrs

Their ages are 18 yrs and 7 years

(a) the volume of the cone is 20/3 in3

hence, option a is correct.

if gloria has "carry over" minutes, (that is, any minutes paid for but not used in a month can be applied to her payment for minutes in the next month,) her total usage for the three months is: total minutes = 320 + 243 + 489 = 1052 minutes number of 200 minute blocks = 1052/200 = 5 r52 (that is 5 with a remainder of 52) rounding up the number of 200 minute blocks gives her usage for the three months as 6 blocks. the cost for six blocks is 6 x $25 = $150 she also has 200 - 52 or 148 carry over minutes if gloria pays each month and unused minutes are lost, applying the rounding up procedure to each month gives: first month usage of 320 minutes rounds up to 2 blocks of 200 minutes for a payment of 2 x $25 = $50 second month usage of 243 minutes rounds up to 2 blocks of 200 minutes for a payment of 2 x $25 = $50 third month usage of 489 minutes rounds up to 3 blocks of 200 minutes for a payment of 3 x $25 = $75 total payments for the three months are $50 + $50 + $75 = $175 get the plan with carry over minutes!