Jill swam 200 meters in 2 minutes and 42 seconds. If each lap is 50 meters long, which time is her estimated, time, in seconds, per lap?
A. 32
B. 60
C. 48
D. 40

D. 40

Step-by-step explanation:

First, calculate the total time she took in seconds.

Convert minutes to seconds using 60 seconds = 1 minute

2 min X 60 s = 120 s

Total time = 120 s + 42 s = 162 s

Calculate the total number of laps.

Convert metres to laps using 50 metres = 1 lap

Laps = 200 m ÷ 50 m = 4 laps

Divide the total time by the number of laps to calculate the unit rate, which is time per one lap.

Since it says to estimate, round 162 seconds.

162 s ≈ 160 s

160 s ÷ 4 laps ≈ 40s/lap

Her estimated time per lap is 40s.

an advantage of the standard deviation is that it increases as the dispersion of the data increases. e. the interquartile range is preferred when the data are not skewed or no have outliers. an advantage of the standard deviation is that it uses all the observations in its computation.

given hc ∥ gd.¯¯¯¯¯¯which statement is true

step-by-step explanation:

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