Mathematics, 17.03.2020 16:52, tubbs45
Eloise started to solve a radical equation in this way: square root of negative 2x plus 1 − 3 = x square root of negative 2x plus 1 − 3 + 3 = x + 3 square root of negative 2x plus 1 = x + 3 square root of negative 2x plus 1 − 1 = x + 3 − 1 square root of negative 2 x = x + 2 (square root of negative 2 x)2 = (x − 4)2 −2x = x2 − 8x + 16 −2x + 2x = x2 + 8x + 16 + 2x 0 = x2 + 10x + 16 0 = (x + 2)(x + 8) x + 2 = 0 x + 8 = 0 x + 2 − 2 = 0 − 2 x + 8 − 8 = 0 − 8 x = −2 x = −8 Both solutions are extraneous because they don't satisfy the original equation.
Answers: 3
Mathematics, 21.06.2019 20:00, maddie53116
Formulate alisha has a number in mind. if she adds three to her number the result is less than five. use this information to write and solve an inequality about alisha's number. then graph the solution set.
Answers: 1
Mathematics, 22.06.2019 02:30, PluggedIn
The first and second steps to solve the equation 3x/5 + 5 = 20.are shown below 3x/5 + 5 - 5 = 20 - 5 3x/5 (5/3) = 15 (5/3)a. addition property of equality b. subtraction property of equalityc. multiplication property of equalityd. division property of equality
Answers: 3
Mathematics, 22.06.2019 04:00, lilque3448
Yesi's dog weighed 5 pounds when she got him. he now yesi's dog weighed 5 pounds when she got him. he now weighs 45 pounds. how much did yesi's dog gain, in ounces?
Answers: 1
Eloise started to solve a radical equation in this way: square root of negative 2x plus 1 − 3 = x sq...
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