A random sample of 16 students selected from the student body of a large university had an average age of 25 years. We want to determine if the average age of all the students at the university is significantly different from 24. Assume the distribution of the population of ages is normal with a standard deviation of 2 years. At a .05 level of significance, it can be concluded that the mean age is . a. significantly less than 25 b. not significantly different from 24 c. significantly less than 24 d. significantly different from 24

Option D) significantly different from 24

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 24

Sample mean, = 25

Sample size, n = 16

Alpha, α = 0.05

Population standard deviation, σ = 2

First, we design the null and the alternate hypothesis

We use Two-tailed z test to perform this hypothesis.

Formula:

Putting all the values, we have

Now,

Since,  

The calculated z statistic does not lie in the acceptance region, we fail to accept the null hypothesis and reject it. We accept the alternate hypothesis.

Thus, it can be concluded that the mean age is

Option D) significantly different from 24

step-by-step explanation: i dont

option 3 . (5x + 1) - (-10x + 6)

step-by-step explanation:

option 1 :

(4x + 3) + (-9x + 4)

or 4x+3 -9x + 4

or -5x + 7

option 2

(x - 2) - (6x - 9)

or x-2-6x + 9

or -5x + 7

option 3

(5x+ + 6)

or 5x + 1 + 10x -6

or 15x -5

option 4

-4x+2x+7-3x

-7x + 2x + 7

-5x + 7

hence only option 3 did   not satisfy the given simplify expression.