The probability that a randomly selected car will be in an accident in the next year in a particular country is 0.0467. If four cars are randomly selected, find the probability that at least one has an accident during the coming year. Round to 4 decimals.

The probability that at least one has an accident during the coming year is 0.1336

Step-by-step explanation:

The probability that a randomly selected car will be in an accident in the next year in a particular country is 0.0467

P(Accident)=0.0467

P(No accident)=1-P(Accident)=1-0.0467=0.9533

Now we are supposed to find four cars are randomly selected, find the probability that at least one has an accident during the coming year

So, P( Out of 4 at least 1 has accident )=1-P( none of the 4 cars has accident)

P(Out of 4 at least 1 has accident )=1-(0.9533)(0.9533)(0.9533)

P(Out of 4 at least 1 has accident )=0.1336

Hence the probability that at least one has an accident during the coming year is 0.1336

too hard the other guy did it

step-by-step explanation:

step-by-step explanation: given equation a = h(b 1+b 2)

also we are given values of a, h and b 1 as :

a = 16, h = 4, and b 1 = 3.

in order to solve it for b 2, we need to plug the given values of   a, h and b 1 .

therefore, plugging values of   a, h and b 1   in given equation, we get

16 = 4( 3 + b 2)

first dividing both sides by 4, we get

4 = 3 + b 2

subtracting 3 from both sides, we get

4 -3 = 3 -3 + b 2

1 = b 2.