Mathematics, 17.03.2020 01:01, hailey5campbelp7d1c0
Evaluate the integral Integral from 0 to 1 Integral from 0 to 3 Integral from 3 y to 9 StartFraction 6 cosine (x squared )Over 5 StartRoot z EndRoot EndFraction dx dy dz by changing the order of integration in an appropriate way.
Answers: 3
![=\int ^1_0[\int^3_0(\int^9_{3y} \frac{6cos x^2}{5\sqrt z}dz)dy]dz](/tpl/images/0549/8008/0bee8.png)
![=\int^1_0[\int^3_0([\frac{6cos x^2 \times \sqrt z}{5\times \frac{1}{2}}]^9_{3y})dy]dx](/tpl/images/0549/8008/f446c.png)
![=\int^1_0[\int^3_0([\frac{12cos x^2 \times( \sqrt 9-\sqrt{3y})}{5}])dy]dx](/tpl/images/0549/8008/95d52.png)
![=\int^1_0[\int^3_0([\frac{12cos x^2 \times( 3-\sqrt{3y})}{5}])dy]dx](/tpl/images/0549/8008/b0604.png)
![=\int^1_0[\frac{12cos x^2 \times( 3y-\frac{\sqrt{3}y^\frac{3}{2}}{\frac{3}{2}})}{5}]^3_0dx](/tpl/images/0549/8008/43eee.png)
![=\int^1_0[\frac{12cos x^2 \times( 3.3-\frac{2\sqrt{3}.3^\frac{3}{2}}{3})}{5}]^3_0dx](/tpl/images/0549/8008/ceabe.png)
![=\int^1_0[\frac{12cos x^2 \times( 9-6)}{5}]dx](/tpl/images/0549/8008/614f5.png)
![=\frac{18}{5}[(x+\frac{sin2x}{2})]^1_0](/tpl/images/0549/8008/180da.png)
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Evaluate the integral Integral from 0 to 1 Integral from 0 to 3 Integral from 3 y to 9 StartFraction...
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