Mathematics, 16.03.2020 23:53, ekmusicent4028
Find two numbers such that their difference and also the difference of their cubes are given numbers; say, their difference is 6 and the difference of their cubes is 504. [Hint: Call the numbers x + 3 and x − 3.]
Answers: 2
![(x+3)^3-(x-3)^3\\= (x+3-x+3)[(x+3)^2+(x-3)^2-(x+3)(x-3)] = 504\\3x^2+9=84\\x^2 = 25\\x = 5 or -5](/tpl/images/0549/6372/56859.png)
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Find two numbers such that their difference and also the difference of their cubes are given numbers...
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