One number is 20 greater than another. If the lesser number is subtracted from three times the greater number, the difference is 84. Find the numbers.

The numbers are 12 and 32.

Step-by-step explanation:

x = One number

x - 20 = Another number

3x - (x - 20) = 84 (If the lesser number is subtracted from three times the greater number, the difference is 84)

Let's solve for x, this way:

3x - (x - 20) = 84

3x - x + 20 = 84

2x = 84 - 20 (Subtracting 20 at both sides)

2x = 64

x = 64/2

x = 32 ⇒ x - 20 = 12

10a^3+277a^2-132a-792

step-by-step explanation:

(2a+11)(5a-12)(foil)

=10a^2-24a+55a-132 =10a^2+31a-132

(10a^2+31a-132)(a+6)

=10a^3+60a^2+31a^2+186a^2-132a-792 =10a^3+277a^2-132a-792

i hope this is what you are looking for : )

throw the computer

step-by-step explanation: