Suppose a process has 3 possible states labeled 1, 2, and 3, and that every hour, it makes a transition to a different state. From state 1, transitions to states 2 and 3 are equally likely. From state 2, transitions to states 1 and 3 are equally likely. From state 3, it always makes a transition to state 1. Find the steady-state distribution. Enter the three steady-state probabilities π1,π2, and π3 as ⟨π1,π2,π3⟩ using the boxes below. Enter exact answers (you may have to use fractions).

Answer is attached below

Step-by-step explanation:

ad = ae + ed = y + 7

similar triangles therefor

ac/ab = ad/ae

6/4 = (y + 7) / y

cross multiply

6y = 4(y + 7)

6y = 4y + 28

2y = 28

y = 14

step-by-step explanation:

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15