What is an equation of the line that passes through the point (1,3) and is
perpendicular to the line x + 3y = 9?

y = 2x + 0

y = mx + C - equation of the line

Step-by-step explanation:

First, find the slope

x + 3y = 9

Using the equation of line

y = mx + C

3y = 9 - x

3y = -x + 9

Divide both sides by 3

3y / 3 = ( -x + 9) / 3

y = ( -x + 9) / 3

We can separate it

y = -x/3 + 9/3

y = -x/3 + 3

m = -1/3

Slope = -1/3

Since weve gotten our slope

Let's use the equation of point slope form

y - y_1 = m(x - x_1)

We are provided with a point

( 1, 3)

x_1 = 1

y_1 = 3

If two lines are perpendicular, their slope will be negative reciprocal

m = -1/3

Perpendicular = +3/1

insert the values

y - 3 = 3(x - 1)

y - 3 = 3x - 3

y = 3x - 3 + 3

-3 cancels +3

y = 3x + 0

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180

its 50 miles away from the starting point