The average price for a gallon of gasoline in the United States is $3.73 and in Russia it is $3.40. Assume these averages are the population means in the two countries and that the standard deviation of $.25 in the United States and a standard deviation of $.20 in Russia. What is the probability that a randomly selected gas station in the United States charges less than $3.50 per gallon

0.17879

Step-by-step explanation:

This is a normal distribution problem

The mean rates of gasoline per gallon for the US is

μ = $3.73

Standard deviation = σ = $0.25

The probability that a randomly selected gas station in the United States charges less than $3.50 per gallon = P(x < 3.5)

We first normalize/standardize/take the z-score

The standardized score for any value is the value minus the mean then divided by the standard deviation.

z = (x - μ)/σ = (3.50 - 3.73)/0.25 = - 0.92

To determine the probability that a randomly selected gas station in the United States charges less than $3.50 per gallon = P(x < 3.50) = P(z < -0.92)

We'll use data from the normal probability table for these probabilities

P(x < 3.50) = P(z < -0.92) = 0.17879

Hope this Helps!!!

"a" determine whether sage found the correct quotient. show your work

step-by-step explanation: