A tall tomato plant with mottled leaves is crossed with a short plant with normal leaves. You get all tall, normal leafed F1 plants. You cross the F1 plants with a short, mottled leafed plant. You observe the following progeny phenotypes: Tall, mottled leaves 395 Short, normal leaves 400 Tall, normal leaves 105 Short, mottle leaves 100 Propose a null hypothesis. What would be the expected values from this hypothesis?

Because the null is that the traits are not linked, the expected values would be:

Tall, mottled leaves 250

Short, normal leaves 250

Tall, normal leaves 250

Short, mottled leaves 250

Step-by-step explanation:

let's cover over the formula of the vertex:

y = a(x – h)^2 + k

in this formula, (h,k) are the vertex, always remember that the positive or negative value of the vertex is based on the sign it has.

for example, if the vertex is -3,-6 then both the x and y value would have the positive sign attached to it and if it were a positive x and y value, then a negative sign would be attached to it.

with that being said, for our problem the x value is a positive one so we are looking for a number with a negative sign next to it, in this case the first and second choice.

however, for the first answer choice it isn't quite part of the formula so we know that the answer choice correctly displays the x value.

to confirm, we can see if the -1 fits correctly with the second answer choice, and as mentioned above a negative number will have a positive sign attached to it. so, for our problem we can see that -1 has been changed to +1, so we can confirm that the second answer choice is correct.

hence, our final answer is y=(x - 1)^2 + 1