In a certain Algebra 2 class of 26 students, 16 of them play basketball and 9 of them play baseball. There are 5 students who play both sports. What is the probability that a student chosen randomly from the class plays basketball or baseball?

  10/13 ≈ 76.9%

Step-by-step explanation:

P(A∪B) = P(A) +P(B) -P(A∩B)

P(plays basketball ∪ plays baseball)

   = P(plays basketball) +P(plays baseball) -P(plays both)

P(plays basketball ∪ plays baseball) = 16/26 +9/26 -5/26 = 20/26 = 10/13

P(plays basketball or baseball) = 10/13 ≈ 76.9%

1. minimum

2. 6400

3. eight

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